If it's not what You are looking for type in the equation solver your own equation and let us solve it.
11x^2=11^2
We move all terms to the left:
11x^2-(11^2)=0
We add all the numbers together, and all the variables
11x^2-121=0
a = 11; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·11·(-121)
Δ = 5324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5324}=\sqrt{484*11}=\sqrt{484}*\sqrt{11}=22\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{11}}{2*11}=\frac{0-22\sqrt{11}}{22} =-\frac{22\sqrt{11}}{22} =-\sqrt{11} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{11}}{2*11}=\frac{0+22\sqrt{11}}{22} =\frac{22\sqrt{11}}{22} =\sqrt{11} $
| X+30+x-30=230 | | -4.5x+27=27 | | 6x+3(3x-1)=36 | | 6x+3(x-1)=36 | | -37-x=62+2x | | 21/4x=-9 | | 7x+3•12=x | | x+4.2=2.5 | | 5x-2=120 | | 3/w=8 | | -62-12x=-7x+28 | | x^/2+6x=17 | | 8=w/30 | | 16x2=19 | | 4(2+3x)–5x+7=-13 | | 2(x+4)^2-7=91 | | -7a^2=630 | | 8−3(5−x)=29 | | (8x-5)+(5x+3)=90 | | |4w+16|=12 | | 5x=18+(2x) | | 12-3a+6a-4=0 | | |4w+16=12 | | -5m^2+6m+-1=0 | | -x+6+3=6-2x | | 3(2x-1)+4(-3x+6)=111 | | 4x^2-371=28 | | -x6+3=6-2x | | 11x-16=13x+18 | | -5m^2+6m-1=0 | | -9a+5-4=23 | | 0.2(x+10)=26-x |